file1 The grep executed in the subshell $(), will print all filenames which contain stringA. I'm using GNU grep 2.5.4. Grep to return lines not containing a character Hello , this is my first topic cause I need your little help I got .txt file, and I want to find lines without letter 'a', so im writing: grep "[^a]" list.txt (list.txt is the file of course) and i have no idea why it's not working because it shows lines with a. Grep NOT 7. We can force grep to only display matches that are either at the start or the end of a line. Do not forget to use the backslash before the pipe character.. For example, display all the lines except those that contains the keyword “Sales”. The grep command allows you to display text that does not match a pattern. I wish it only to return lines that DO NOT contain 1234 at the end. Another approach is to separate what to exclude with grep by using a pipe to separate each match, like so: grep -Ev "word1|word2" example.txt grep -v "grep" takes input line by line, and outputs only the lines in which grep does not appear. egrep -i '12-12. This command returns: 2 medium eggs. You can also use grep directly on files just as before as well: grep -v -e "Word1" -e "Word2" example.txt. Let’s retrieve a list of all the ingredients which are not liquid. You might be able to make it work with a complex regular expression, but you might be better off just doing: grep '[AB]' somefile.txt | grep -v '2' The R equivalent of that would be: grep("2", grep… Users may make use of the -v option to print inverts the match, which means it would match only those lines that do not contain the given word. The file names are listed, not the matching lines. As long as your filenames do not contain spaces, tabs, newline or wildcard characters, and if your grep supports the -L option, you can do it as follows: $ cat file1 stringA stringC $ cat file2 stringA stringB $ grep -L stringB $(grep -l stringA file?) Currently, this is my workaround. To print files that do not contain extends SomethingSomething anywhere, use the -L option: grep -L -E 'extends[[:space:]]+SomethingSomething' FILENAME… Some versions of grep do not have the -L option (it is not specified by POSIX). Grep NOT using grep -v. Using grep -v you can simulate the NOT conditions. 400g self raising flour *\swarning' log.file > tmp.txt egrep -i -v '1234' tmp.txt grep generally does not work very well for doing a positive and a negative search in one invocation. grep -v 'pattern1' filename. Start and End of Lines. And of course, we can look for files that don’t contain the search term. 250g golden caster sugar. When I try "grep [^834] file.txt" it still prints all the lines containing 834 but just doesn't highlight them. grep -L "sl.h" *.c. Any lines that contain “Word1” or “Word2” will be excluded from the printed results. Without -v, it would output only the lines in which grep does appear. -v option is for invert match. For instance, print all lines that do not contain the word par by using the following command: grep -v par /path/to/file 9 How to list only the names of matching files i.e It matches all the lines except the given pattern. I'm trying to get Grep to print all lines in a txt file that do not contain the numbers 834. The awk solution is what I would use, but a slightly smaller process to launch is sed and it can produce the same results, but by substituting the PATH= part of the line with "", i.e.. sed -n 's/^Path=//p' file The -n overrides seds default behavior of 'print all lines' (so -n = no print), and to print a line, we add the p character after the substition. 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